x-1=0.25x^2

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Solution for x-1=0.25x^2 equation: 



x-1=0.25x^2

We move all terms to the left:

x-1-(0.25x^2)=0

We get rid of parentheses

-0.25x^2+x-1=0

a = -0.25; b = 1; c = -1;
Δ = b2-4ac
Δ = 12-4·(-0.25)·(-1)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-1}{-0.5}=+2$

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